Chemistry, 29.01.2020 17:05 ayyyyyyyydubs

If 38.5 ml of lead (ii) nitrate solution reacts completely with excess sodium iodide to yield 0.0628 g or precipitate, what is the molarity of lead (ii_ ion in the original solution.. i was wondering if any could tell me how to solve this i have been looking over my chapter and can't figure out what i need to do..

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If 38.5 ml of lead (ii) nitrate solution reacts completely with excess sodium iodide to yield 0.0628...