Calculate the mean free path of air molecules at a pressure of 7.00×10^−13 atm and a temperature of 303 k . (this pressure is readily attainable in the laboratory.) model the air molecules as spheres with a radius of 2.00×10^−10 m .

An athlete swings a ball, connected to the end of a chain, in a horizontal circle. the athlete is able to rotate the ball at the rate of 8.13 rev/s when the length of the chain is 0.600 m. when he increases the length to 0.900 m, he is able to rotate the ball only 6.04 rev/s. (a) which rate of rotation gives the greater speed for the ball? 6.04 rev/s 8.13 rev/s (b) what is the centripetal acceleration of the ball at 8.13 rev/s? m/s2 (c) what is the centripetal acceleration at 6.04 rev/s? m/s2